1/1-x^2=-I3x-2I+5

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Solution for 1/1-x^2=-I3x-2I+5 equation:



1/1-x^2=-3x-2+5
We move all terms to the left:
1/1-x^2-(-3x-2+5)=0
We add all the numbers together, and all the variables
-x^2-(-3x+3)+1/1=0
We add all the numbers together, and all the variables
-1x^2-(-3x+3)=0
We get rid of parentheses
-1x^2+3x-3=0
a = -1; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-1)·(-3)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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